A velocity selector consists of electric and magnetic fields described by the expressions vector E = E k-hat and vector B = B j-hat, with B = 0.0130 T. Find the value of E such that a 830 -eV electron moving along the negative x axis is undeflected?
The Attempt at a Solution
So I know i want to find E such that an electron with velocity = -v i-hat is undeflected. I also know form Lorenz's force that:
F = q[E + (v x B)] = 0
So i really just need to make E equal to the cross product (v x B) but opposite sign. I did this using using the fact that 830 -eV is the kinetic energy, set this equal to 0.5mv^2 and solved for v to be 4.268837e16 m/s.
Next I computed the cross product to get a value of -5.549e14 k-hat. So E should be equal to this but with opposite sign, not working however for my online submission, any suggestions as to where I am going wrong?