Electric Potential Due to Unevenly Charged Disk - Help/Hints Needed

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    Integral
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Discussion Overview

The discussion revolves around finding the electric potential due to a disk with an uneven charge distribution. Participants explore various integration techniques to solve the integral involved in the calculation.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in solving the integral and seeks hints on whether to use integration by parts or another method.
  • Another participant suggests a substitution method involving hyperbolic functions, specifically r = x sinh(t).
  • A different participant proposes using trigonometric substitution, suggesting tan(θ) = r/x and drawing a triangle to simplify the integral.
  • A later reply indicates that the original poster resolved the issue using u-v substitution, taking u = r² and dx = r/(r² + x²)⁹.⁵.

Areas of Agreement / Disagreement

Participants offer different methods for solving the integral, indicating multiple competing views on the best approach. The discussion does not reach a consensus on a single method.

Contextual Notes

Some methods proposed depend on specific substitutions that may not be universally applicable, and the effectiveness of each approach may vary based on the integral's complexity.

Who May Find This Useful

Students or individuals interested in mathematical techniques for solving integrals related to electric potential in physics contexts.

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i have to integrate to find the electric potential due to a disk of charge with an uneven charge distribution. i was able to set up the intergral but i can't solve it. should i do integration by parts (i tried it) or use something else. just give me a hint

int ( r^3/[(x^2 + r^2)]^.5) dr (x is a constant)

thanks
 
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Make the substitution

[tex]r=x\sinh t[/tex]

Daniel.
 
>.< I don't know Daniels way, Id go with trigonometric substitution, tan theta = r/x. Draw a triangle, you see that the hypotnuse is your denominator. Just solve for everything and sub them in, it reduces to [tex]x^3\int \tan^3 \theta \sec \theta d\theta[/tex].
 
yea i figured it out. i did uv substitution, takeing u=r^2 and dx= r/(r^2+x^2) ^9.5)

thank you for everyone who gave advice. :D
 

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