Electric Potential: Electric charge surrounded by two spherical shells

AI Thread Summary
A point charge of -8 μC is enclosed by two conducting spherical shells, with the outer shell carrying a charge of -10 μC. The problem requires finding the potential difference between the inner and outer radii of the shells. The electric field is calculated using Coulomb's law, and the relationship between electric field and potential is established through integration. The user seeks clarification on using Gauss' Law to determine the equivalent point charge and the correct limits for integration. The discussion emphasizes the integration process for calculating the potential difference across the specified radii.
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Homework Statement


A point charge q = -8 μC is surrounded by two thick, conducting spherical shells of inner and outer radii
a1 = 0.3 m, a2 = 0.4 m, a3 = 0.7 m, and a4 = 0.8 m respectively. The inner shell is uncharged; the outer
shell has a net charge Q = -10 μC. At this point in the problem, the potential at infinity is unspecified.

(c) V(a2) - V(a3) = ____________________ V

Homework Equations



E = kQ/r^2

Guass’ Law: ϕ= ʃE·dA

V0 = - ʃE·dl

HELP: Identify the equivalent point-charge that gives the same electric fields everywhere in the region a2 < r < a3 as the specified charge distribution.
HELP: Use the electric potential function that corresponds to the equivalent point-charge problem.

The Attempt at a Solution



Electric field of the sphere at a2:
E = k(-8uC)/(.4^2) = -449500 N/C

Im stuck. I figured out the first two problems but I am not sure how to relate the electric field to the potential, and I am not sure how to get the equivalent point charge. I assume I need to use guass' law to find the equivalent point charge but my queastion is do I just use the difference of a2 and a3 for the radius?
 
Last edited:
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Assuming that the spherical shells are centered at the origin:

What is the electric field a distance r from the origin, where a2 < r < a3 ?

For a2 < r < a3:

V(r)-V(a_2)=-\int_{a_2}^{\,r}E(r)\,dr\ .
 
Ah. So I just integrate from 0.4 to 0.7? I feel stupid sometimes lol.

Va-Vb = - ʃ(kQ/r^2)dr = kQ((1/a)-(1/b))

Thanks for the help by the way!
 
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