Electric Potential Energy Spherical Shells

AI Thread Summary
The discussion focuses on deriving the total electric potential energy of a uniformly charged solid sphere by considering it as a series of concentric shells. The participants suggest using the equation U = ∫4πr²k_e(q/r)dr, where q represents the total charge and k_e is Coulomb's constant. The charge density ρ is defined as ρ = Q/(4/3)πr³, and the integration involves substituting dq with the expression for the charge of the spherical shell. The final expression for the small potential energy dU is derived as dU = (16/3)π²kρ²R⁴dR, indicating the complexity of the integration process. The conversation highlights the importance of careful calculations and the potential for errors in deriving the total electric potential energy.
JosephK
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Homework Statement



A solid sphere of radius R has a uniform charge density ρ and total charge Q. Derive an expression for its total electric potential energy. Suggestion: Imagine that the sphere is constructed by adding successive layers of concentric shells of charge dq = (4\pi r^{2} dr) ρ and let dU = Vdq. (Use any variable or symbol stated above along with the following as necessary: ke.)

Homework Equations



U = \int4\pir^{2}k_{e}\frac{q}{r}dr

\rho=\frac{Q}{\frac{4}{3}\pi r^{3}}



The Attempt at a Solution



The sum of all dq is Q.

U = qV - q is test charge
U = q k_{e}\frac{Q}{r} - equation of voltage substituted

dQ = dq k_{e}\frac{Q}{r} -small potential energy with respect to small charge

dQ = 4k_{e}\pi\rho\frac{Q}{r} r^2 dr - dq plugged in

Then I integrated both sides.
 
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I'm having a little trouble following that.
It seems to me the dQ for the spherical shell is 4πR²ρ*dR.
The work done to bring dQ in from infinity to R is dU = kQ/R*dQ.
And Q up to radius R is 4/3*πR³ρ.
Combined, dU = 16/3π²k ρ²R⁴dR
Check carefully; I make mistakes.
 
Thank you
 
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