Electric Potential Vs. Electric Potential Energy Concepts

AI Thread Summary
When a positive charge moves towards a positively charged sphere, its electric potential (V) increases, but the electric potential energy (Ee) can decrease if the charge is negative. The relationship V = Ee/q indicates that potential is defined per unit charge, meaning the potential energy is influenced by the nature of the charge approaching the sphere. As a negative charge approaches a positive charge, the electric potential energy decreases due to the attractive force, despite the electric potential increasing. Understanding the distinction between electric potential and electric potential energy is crucial in analyzing charge interactions.
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Homework Statement


A charge moves towards a positively charged sphere, as it does, it's electric potential (V) increases. Give an instance on when the Electric Potential Energy (Ee) will decrease.

Homework Equations


V= Ee/q

The Attempt at a Solution


Alright, This is basically a theory question. Anyways, I've been having some difficulty with this, as to my understanding when a charge gains electric potential as it moves towards a positivity charged sphere (Which, from this we can assume that the charge moving towards is positive,) and the electric potential is increasing because work is being done on it etc, because of this wouldn't the Electrical Potential Energy also increase? Since it'll have more electrical potential energy as it gets closer-since the two charges naturally want to repel each other. I'm thinking this might be an error, since electric potential is directly proportional to the Electrical Potential Energy. (According to V=Ee/q)

Any thoughts on the matter would be greatly appreciated.
 
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Potential is defined with respect to a charge q. That potential is kq/r and is not affected when a second charge approaches it.

Now, you have a choice of two polarities for the second charge. Take one polarity at a time and figure how the potential energy of that second charge is affected as it approaches the first charge (which is positive).
 
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