1. The problem statement, all variables and given/known data A meter is shunted by a parallel resistance. a) Determine the required value of the shunt resistance if the maximum value of the current I, is 200A. The meter can read a maximum of 1 mA and has a resistance of 0.1 Ω. b) If the shunt is made of copper and has a cross-cectional area of 25cm2 calculate its required length. (for copper take ρ as 1.7x10-8Ωm 2. Relevant equations ohms law (V=I.R) R = ρ.(l/A) 3. The attempt at a solution a) full scale voltage = 0.001 * 0.1 = 0.0001 v shunt resistance Rshunt = 0.0001/200 = 0.5x10-6Ω Rshunt = 0.5 mΩ b) 0.5x10-6 = (1.7x10-8) * ( l / 0.252) (0.5x10-6 / 1.7x10-8) * 0.252 = l l = 1.83824 cm does any of this look right? Thanks.