Engineering Electrical engineering, RLC circuit

AI Thread Summary
In a series RLC circuit with R=5 ohms, L=1H, and C=10uF, the task is to plot the output voltage V0(t) across the resistor as a function of frequency, focusing on a range that includes the resonance frequency. The resonance frequency for the LC components is determined by the formula f0 = 1/(2π√(LC)). A sufficiently large frequency band should encompass a couple of decades above and below this resonance frequency to observe significant changes in voltage behavior. If minimal activity is noted outside of this range, adjustments can be made to narrow the frequency band. This approach will help in analyzing the circuit's response effectively.
beanryu
Messages
90
Reaction score
0
Alright, here I come again for help!

In a series R, L, C circuit, the values of the passive elements are R=5ohm, L=1H, and C=10uF. The output voltage is taken across R, and te input voltage signal is of variable frequency. Using Electronics Workbench, obtain a plot of V0(t) as a frequency f over a sufficiently large frequency band which is roughly bisected by the resonance frequency.

Okay, all I don't get is "obtain a plot of V0(t) as a frequency f over a sufficiently large frequency band which is roughly bisected by the resonance frequency."
What is meant by "a sufficiently large frequency band which is roughly bisected by the resonance frequency."?

THANK YOU! THIS IS A TAke hoME QUIZ!
 
Physics news on Phys.org
Hint -- the only things resonating in the circuit are the L & C, since the resistor cannot store energy. So what is the resonant frequency of an LC circuit? And for sufficiently large frequency band, start with a couple of decades above and below the resonant frequency, and pare it down if nothing interesting is happening outside +/1 one decade. Let us know what you find...
 

Similar threads

Replies
40
Views
5K
Replies
21
Views
1K
Replies
2
Views
3K
Replies
4
Views
1K
Replies
1
Views
2K
Replies
11
Views
12K
Replies
7
Views
2K
Back
Top