Electrical Generator and rotating coil

AI Thread Summary
An electric generator with a rotating coil in a magnetic field is analyzed to determine the speed required to induce an alternating emf of 11.00 V. The relevant equation for induced emf is modified to Eo = NBAω, where N is the number of turns, B is the magnetic field strength, A is the area of the coil, and ω is the angular speed. After calculations, the angular speed was found to be 130.99 rad/s. To convert this to revolutions per second, the result is divided by 2π, yielding a final answer of 20.85 rev/s. The discussion emphasizes the importance of unit conversion in solving the problem correctly.
SereneKi
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Homework Statement



An electric generator consists of a rectangular coil of wire rotating about its longitudinal axis which is perpendicular to a magnetic field of B = 1.70 × 10-2 T. The coil measures 13.00 cm by 19.00 cm and 200.00 turns of wire. The ends of the wire are connected to an external circuit. At what speed must you rotate this coil in order to induce an alternating emf of amplitude 11.00 V between the ends of the wire? Give you answer in rev/s. Do not enter the units.


Homework Equations



Eind=-N d(BAcos(theta))/ dt

The Attempt at a Solution



I know that because this has a turning coil in a magnetic field, the above equation can become Eo=-NBA

and thus Eo=0.08398 V

I just don't know where to go form here or how you are supposed to find the speed?
 
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You'll need to express θ as a function of time so that you can carry out the time derivative in your expression.
 
TSny said:
You'll need to express θ as a function of time so that you can carry out the time derivative in your expression.

Eind=-NBA*dcos(theta)/dt

is that what you meant?
 
You can assume that the generator is rotating at constant angular speed ω. So, θ = ωt.
Using that, can you evaluate d(cosθ)/dt?
 
TSny said:
You can assume that the generator is rotating at constant angular speed ω. So, θ = ωt.
Using that, can you evaluate d(cosθ)/dt?

d(cos(wt))/dt

θ=2(pi)ft = wt

emf=NBAw

is that right?
 
SereneKi said:
emf=NBAw

is that right?

Looks good to me.
 
TSny said:
Looks good to me.

so w= 11/ 200 * 1.7*10^-2 * .13 * .19

w=130.99

What now, Lon capa says that isn't the answer
 
SereneKi said:
so w= 11/ 200 * 1.7*10^-2 * .13 * .19

w=130.99

What now, Lon capa says that isn't the answer

What are the units of w in emf= NBAw?

Note that you are asked to find the rotation rate in rev/s.
 
TSny said:
What are the units of w in emf= NBAw?

Note that you are asked to find the rotation rate in rev/s.

They are rad/s! So 130.99 / 2pi = 20.85 which is right! thank you so much!
 

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