Electricity and Magnetism: Forces on Conductors in Magnetic Fields

AI Thread Summary
The discussion focuses on calculating the force per unit length on a straight conductor in a magnetic field, where the force is determined by the equation F/l = BIsinφ, with the force acting perpendicular to both the magnetic field and the conductor. For a square aluminium frame in a magnetic field, the electrical resistance is expressed as R = L/σA, while the total mass can be calculated using the formula ρV, where V is the volume of the frame. The challenge arises from missing parts of the frame, complicating the volume calculation. Participants seek clarification on how to address the incomplete frame in their calculations. Overall, the discussion emphasizes the importance of understanding the relationships between current, magnetic fields, resistance, and mass in conductive materials.
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Homework Statement



(i) What is the strength and direction of the force per unit length acting on a straight conductor carrying an electrical current, I, in a magnetic field, B?

(ii) The figure below shows a square frame of aluminium set at an angle θ to the direction of a strong static magnetic field, B, parallel to the x-axis (the y-axis is vertical). The frame has sides of length L and the arms have cross-sectional area A, with L >> √A. Write down expressions for the electrical resistance (for currents flowing around the frame) and the total mass if the density and conductivity of aluminium are ρ and σ respectively.

(iii) left out for the moment

Homework Equations



The Attempt at a Solution



(i) F = B x Il,
so F/l = BIsinφ, where φ is the angle between the direction of force and the length of the conductor and the force acts in a direction which is perpendicular to the magnetic field and the length of the conductor.

(ii) Electrical resistance R = L/σA

Total mass = ρV = ?

Any comments would be greatly appreciated.
 

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Well, V=LA.
 


Well, I know that but the problem is part of the frame is missing, so don't know how to take that into account.
 
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