Electricity and Magnetism: Forces on Conductors in Magnetic Fields

Click For Summary
SUMMARY

The discussion focuses on calculating the force per unit length acting on a straight conductor carrying an electrical current in a magnetic field, specifically using the formula F/l = BIsinφ. Additionally, it addresses the electrical resistance of a square aluminium frame set at an angle θ to a magnetic field, with the resistance calculated as R = L/σA. The total mass of the frame is derived from the volume V = LA, considering the density ρ of aluminium. The challenge arises from the incomplete frame affecting the calculations.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically the Lorentz force law.
  • Familiarity with electrical resistance calculations, particularly for conductors.
  • Knowledge of material properties, including density (ρ) and conductivity (σ) of aluminium.
  • Basic geometry related to angles and areas in physics.
NEXT STEPS
  • Study the Lorentz force law in detail to understand forces on conductors in magnetic fields.
  • Research the principles of electrical resistance in conductors, focusing on the formula R = L/σA.
  • Explore the properties of aluminium, including its density and conductivity, for practical applications.
  • Investigate the effects of geometry on magnetic forces and resistance in electrical circuits.
USEFUL FOR

Students and educators in physics, electrical engineers, and anyone involved in the study of electromagnetism and its applications in conductive materials.

spaghetti3451
Messages
1,311
Reaction score
31

Homework Statement



(i) What is the strength and direction of the force per unit length acting on a straight conductor carrying an electrical current, I, in a magnetic field, B?

(ii) The figure below shows a square frame of aluminium set at an angle θ to the direction of a strong static magnetic field, B, parallel to the x-axis (the y-axis is vertical). The frame has sides of length L and the arms have cross-sectional area A, with L >> √A. Write down expressions for the electrical resistance (for currents flowing around the frame) and the total mass if the density and conductivity of aluminium are ρ and σ respectively.

(iii) left out for the moment

Homework Equations



The Attempt at a Solution



(i) F = B x Il,
so F/l = BIsinφ, where φ is the angle between the direction of force and the length of the conductor and the force acts in a direction which is perpendicular to the magnetic field and the length of the conductor.

(ii) Electrical resistance R = L/σA

Total mass = ρV = ?

Any comments would be greatly appreciated.
 

Attachments

  • IMAG0009.jpg
    IMAG0009.jpg
    31.7 KB · Views: 440
Last edited:
Physics news on Phys.org


Well, V=LA.
 


Well, I know that but the problem is part of the frame is missing, so don't know how to take that into account.
 

Similar threads

Replies
10
Views
2K
Replies
9
Views
2K
Replies
2
Views
1K
Replies
1
Views
2K
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
Replies
11
Views
2K