Electricity flow in a light sensitive theft alarm

AI Thread Summary
The discussion revolves around understanding the operation of a light-sensitive theft alarm circuit, particularly how electricity flows and activates the siren. The circuit begins at the positive side of the power source, with current splitting between components, including the Light Dependent Resistor (LDR1). The LDR's resistance increases in darkness, allowing the circuit to trigger the siren when light levels drop. Participants emphasize the importance of analyzing the circuit's voltage and current paths to grasp its functionality. The conversation concludes with a focus on the relationship between light intensity and resistance in the context of the circuit's operation.
FaridAbhmad
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I'm not learning physics in English, so terminolgy might be wrong.

1. Homework Statement

How does this circuit function? Where do the electricty flow?

Homework Equations


No equations

The Attempt at a Solution


Not sure what to put here?

My question is basically how it work. As far as I know, the circuit starts at the positive side of the power source, and "splits" by some part of the electrons going to the LDR1 and the other part continues going to the right, and continues branching everytime it can. But how does the light sensitivity thing work? Where do the electricity go for it to start the siren/buzzer? There is nothing near LDR1, so what activates it and what makes it stop, if there is no resistor or anything there to stop it?

Does this make sense? New to physics.
 

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Is this homework?
 
Hey @FaridAbhmad, welcome to PF.

For the useful equations, what would be nice there is the necessary voltage and current equations. (The voltage across a resistor equals what?)

The attempt at the solution should be either an attempt at a time or a frequency analysis (in general) depending on whether it's ac or dc (this one happens to be dc). So setting up your voltage equations and using V=IR should be sufficient.
 
BiGyElLoWhAt said:
Hey @FaridAbhmad, welcome to PF.

For the useful equations, what would be nice there is the necessary voltage and current equations. (The voltage across a resistor equals what?)

The attempt at the solution should be either an attempt at a time or a frequency analysis (in general) depending on whether it's ac or dc (this one happens to be dc). So setting up your voltage equations and using V=IR should be sufficient.
Do you mean if it is in Ohms? The resistor is that atleast, don't even know it you use something else to measure.
100k, 10k, 4.7k ohms

I'm not supposed to calculate or something. This is just to understand how a circuit works. But I don't know how this works. I need help understanding what makes the siren start, and what makes it stop? Where does the electricity go?

EDIT: yes, it's homework.
 
Well, without going through and analyzing it, I'm not really sure, it's a fairly complex circuit. Start at the battery, and trace every path. Write the sum of the voltage equations, make sure you keep track of the parallel and series components appropriately, and if you get stuck then maybe I can help more.
 
As it's homework we aren't meant to give you the answer, just hints so you can solve it yourself.

I would start at the siren/buzzer. What has to happen for the siren/buzzer to sound?
 
CWatters said:
As it's homework we aren't meant to give you the answer, just hints so you can solve it yourself.

I would start at the siren/buzzer. What has to happen for the siren/buzzer to sound?
Alright, will continue trying.
It has to be dark. When it gets darker the siren will sound.

Can I ask another question then? It is not part of the homework but is related to this.
In class when we built this circuit. We also measured Ohms to it. I found out that the darker it is the higher the resistance is. less light = high resistance. But how does this happen?
 
The sensors could possibly break down under light, making it easier for the current to flow.
 
FaridAbhmad said:
Alright, will continue trying.
It has to be dark. When it gets darker the siren will sound.

What I meant was..

For the buzzer to sound electricity has to be flowing through it so T1 must be ON.
For T1 to be ON...

Edit: It might be easier to start with the assumption that the buzzer is OFF. That implies T1 is OFF. What about T2... Go around the circuit marking it up with approximate voltages or logic levels.
 
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FaridAbhmad said:
In class when we built this circuit. We also measured Ohms to it. I found out that the darker it is the higher the resistance is. less light = high resistance. But how does this happen?

LDR1 is a Light Dependant Resistor aka Photoresistor..

http://en.wikipedia.org/wiki/Photoresistor
 
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