Electro chem, basic concept problem

AI Thread Summary
To determine which species can oxidize Fe to Fe2+, the standard reduction potentials are compared. The relevant half-reaction for Fe is Fe2+ + 2e- --> Fe with a potential of -0.44 V. Species with higher reduction potentials than -0.44 V can oxidize Fe; thus, Cu2+ (+0.34 V) is the only species that meets this criterion. Zn2+ (-0.76 V), Al3+ (-1.67 V), and Mg2+ (-2.28 V) cannot oxidize Fe due to their lower potentials. Therefore, Cu2+ is the correct answer for this electrochemical problem.
geffman1
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hey guys I've got another problem, any conceptual help and help would the questions would be greatfully apprectiated. thanks

Homework Statement



From a consideration of the data below determine which of the given species will oxidize Fe to Fe2+:
Data
Fe2+ + 2e- --> Fe; E° = -0.44 V
Zn2+ + 2e- --> Zn; E° = -0.76 V
Al3+ + 3e- --> Al: E° = -1.67 V
Mg2+ + 2e- --> Mg; E° = -2.28 V
Cu2+ + 2e- --> Cu; E° = +0.34 V

a. Zn2+

b. Al3+

c. Mg2+

d. Cu2+

e. none of these



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d.) Arrange the values on a number line.
 
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