Electromagnetic Radioation Optics

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SUMMARY

The discussion centers on calculating the image distance for a convex mirror with a focal length of 16 cm, using the mirror formula 1/f = 1/do + 1/di. The user attempted to solve for the image distance (di) given an object distance (do) of 3.0 m (300 cm). The correct calculation yields an image distance of -15 cm, indicating that the image is virtual and located behind the mirror.

PREREQUISITES
  • Understanding of mirror formulas, specifically 1/f = 1/do + 1/di
  • Knowledge of convex mirror properties and image formation
  • Basic algebra skills for manipulating equations
  • Familiarity with the concept of virtual images in optics
NEXT STEPS
  • Study the properties of convex mirrors and their applications in real-world scenarios
  • Learn about the significance of negative image distances in optics
  • Explore the derivation and applications of the mirror formula in different types of mirrors
  • Investigate the differences between real and virtual images in various optical systems
USEFUL FOR

Students studying optics, physics enthusiasts, and anyone interested in understanding the principles of image formation in convex mirrors.

AndrewTT
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User informed about mandatory use of homework template.
A convex mirror has a focal length of 16cm. How far behind the mirror does the image of a person 3.0m away appear?

I've tried using the equation
1/f = 1/do + 1/di

The answer to the solution is -15cm but I'm not sure how to get there. I'm thinking that it might have something that deals with theory to solve this.
 
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Hi AndrewTT and welcome to PF!

As you can read in our guidelines, you need to provide a little more information on your attempt. For example:
AndrewTT said:
I've tried using the equation
1/f = 1/do + 1/di
What did you get when you tried to use this?
 

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