Electromagnetic waves and astronaut

AI Thread Summary
An astronaut, floating 20.0 meters from a space shuttle with a total mass of 150kg, attempts to use a 220w flashlight as a "light rocket" to reach the shuttle. The initial calculations using the equation E=c*p led to confusion, with one participant mistakenly calculating a travel time of 1250000 hours instead of the expected 25.1 hours. Key discussions focused on the need to compute force exerted by the beam and the correct interpretation of power as it relates to acceleration. A significant error identified was the omission of the (1/2) factor in the distance-time-acceleration relationship. Accurate calculations and unit tracking are crucial for solving this physics problem effectively.
yogi41
Messages
6
Reaction score
0

Homework Statement



I've been trying to do this problem for about 2 hours now. I can't seem to find the right equations to use. Any help would be appreciated

A spacewalking astronaut servicing an orbiting space telescope has run out of fuel for her jet pack and is floating 20.0 m from the space shuttle with zero velocity relative to the shuttle. The astronaut and all her gear have a total mass of 150kg. If she uses her 220w flashlight as a "light rocket," how long will it take her to reach the shuttle?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
How about this one, E=c*p. Where E is the energy of the light beam, p is it's momentum and c=speed of light.
 
the answer is supposed to be 25.1 hours. When i used E=c*p i ended up getting 1250000 hours. Am i doing a simple calculation wrong?
 
I get the 25 hour figure as well. Did you compute the force exerted by the beam? What are some of your intermediate results?
 
well i first calculated p 220w/3x10^8 which was 7.33 x 10^-7
then i divided that answer by 150kg to get 4.89 x 10^-9 which I'm assuming is my velocity
from there i divided the distance from the ship which was 20m to get 2.44 x 10^-10
and then i divided 1/2.44 x 10^-10 to get my answer in seconds
 
Keep track of units. Then you won't have to 'assume' that something is a velocity. Power/c is a force. (Power/c)/mass is an acceleration. Not a velocity.
 
Last edited:
so I took the square root of the 2.44 x 10^-10 1/s^2 to get 1.56 x 10^-5 1/s and i flipped the sign by 1/1.56 x 10^-5 1/s to get 64018.4 but then when i convert it back to hours it's only 17.8 hours when it is supposed to be 25.1 hours. Where did i make the mistake? thanks for the help
 
The relation between distance, time and acceleration is d=(1/2)*a*t^2. Looks like you dropped the (1/2).
 
Back
Top