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Electromagnetism vectors question. Calculating electric flux of displacement vector

  1. Jan 20, 2012 #1
    Using cylindrical co-ordinates (r, theta, z), calculate the electric flux
    phi=integral D . dS
    when the displacement vector D is given by:
    D=10ezcos(theta)/r2 . kr + z2sin(theta)/r2 . Kz and the surface S is part of a cylinder of radius a=0.3, defined by 0 is less than or equal to z which is less than or equal to 1 and 0 is less than equal to theta which is less than or equal to pi/4


    I’ve put the equation in the cylindrical co-ordinates:

    (10ezcos(theta)/r2, 0, z2sin(theta)/r2)

    From there I’ve written out S as S(Sr, Stheta, Sz)

    I know that the perpendicular lines define the surface. In this case Sz is perpendicular which means than Sr is the main component.
    Then:

    D . DS = DrdSr + DthetadStheta + DzdSz

    But I don’t know where to go from here..... Any help?
     
  2. jcsd
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