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Problem: Give the quantum numbers (n, l, ml, ms) for each electron in one neutral carbonatom in ground state.

My solution: I look at a table to get the electron configuration and for a carbonatom i get 1S^2 2s^2 2p^2

For s

n=1, l=0, ml=0, ms=+-1/2

n=2, l=0, ml=0, ms=+-1/2

n=2, l=1, ml=-1,0,1, ms=??

For p

n=2, l=0, ml=0, ms=??

n=2, l=1, ml=-1,0,1, ms=??

My question: From the two first shells from s i get 4 electrons, so i have to get 2 more, but from where do i get those 2? It must be som kind of rule but i can't find any. pls help :)

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# Homework Help: Electron configuration quantum numbers

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