- #1
skate_nerd
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Homework Statement
This problem has a photon that was emitted by an electron orbiting a hydrogen atom that dropped from n=5 orbit to n=2. I need to find out, if this photon emitted an electron from the n=4 orbit of another hydrogen atom, what the k.e. of this electron would be.
Homework Equations
1/λ=R(1/n_f^2-1/n_i^2)
E=hc/λ
not sure of what else i need
The Attempt at a Solution
So far I found the wavelength using the first equation I listed, and then from this found the energy of the first emitted photon. I got 2.856 eV. I'm pretty sure I am supposed to use this information to find out what the k.e. of the electron that this photon emits is, but I am unsure of how to do that.
At first I thought maybe the energy of the photon was equal to the total energy of the electron, and so 2.856 eV=k.e.+rest energy of the electron, but this obviously didnt work (got a negative number for k.e.).
Im sure there's just some equation I am missing. If someone would fill me in that would be appreciated.