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Electron transition states

Which electron transitions in singly-ionized Helium (He+) yield photons in the blue (450-500 nm) portion of the electromagnetic spectrum? What are their wavelengths, and what transitions do they represent?

2. Homework Equations
hear is the equation I tried to use an equation creator but did not work, sorry;

1/wave length=Z^2*R(1/nf-1/nI)
where Z is the charge, for Helium=2
and R=1.097*10^7 m^(-1)

3. The Attempt at a Solution
ok, I found the wave length to be 455 nm when nf=5 and nf=4, that is the only one I could find, and I do not understand how to answer the first part. Is the found nf and nI the electron transitions, and what does it mean by what transitions does it represent? Thank you
 
Last edited:

Answers and Replies

I just realize that I made the charge on Helium 2, but it should be 1, I think, and then the only nf and nI I can find is 3 and 7 respectively giving wave length of 478nm. I believe I am over thinking the first part and believe the found nf and ni is the transition but I am confused on the last part still.
 

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