Electrostatic force on the particle

AI Thread Summary
A charged particle located inside a uniformly charged shell experiences no net electrostatic force from the shell, which is a confirmed fact for spherical shells. This phenomenon occurs because the forces exerted by different parts of the shell cancel each other out due to symmetry. Although individual charges within the shell are at varying distances from the particle, the geometry ensures that the net effect is zero. For non-spherical shells, this principle holds approximately true if the distance from the particle to the shell is significantly larger than the shell's dimensions. Understanding this concept involves recognizing how the distribution of charge and distances interact to balance the forces.
young physical
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if a charged particle ic located inside a shell of uniform charge there is no net electrostatic force on the particle from the shell.
1st is this fact?
2nd if it is so please explane it to because there is some distance between the particle and other chargeds in shell every one has different distance from anther?.:smile:
 
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The electrostatic force is directly proportional to charge.
The electrostatic force is directly proportional to 1/r^2.
But the charge is directly proportional to r^2.

Think about this and see for yourself if it is true.
 
young physical said:
if a charged particle ic located inside a shell of uniform charge there is no net electrostatic force on the particle from the shell.
1st is this fact?
Yes, it is a fact for spherical shells. For non-spherical shells it will be approximately true if the distance from the particle to the shell is large compared to the change in "radius" of the shell.

2nd if it is so please explane it to because there is some distance between the particle and other chargeds in shell every one has different distance from anther?.:smile:
I have no idea what you mean by "every one has different distance". Isn't that always true?

Draw four straight lines from one side of the shell through the particle to the other side. The area of the shell contained within those four lines on one side offsets the area on the other side because, as Haywire said, the the ratio of the two areas is equal to the ratio of the distances squared, while the ratio of the forces due to the charge in each area is equal to the one over the ratio of the distances squared.
 
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