Electrostatics: Conducting Sphere in Uniform Electric Field

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A small conducting sphere with mass M and charge Q is suspended in a uniform electric field E, making a 30-degree angle with the field. The tension in the string was calculated as 0.023 N, but clarification was needed on how to relate the electric field to the tension using Newton's third law. The magnitude of the electric field was calculated as approximately 444,444.4 N/C, though the method used was questioned. If the string is cut, the sphere will move down and to the right due to the forces acting on it. The discussion emphasizes the importance of accurately analyzing forces and using correct formulas in electrostatics problems.
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Homework Statement


A small conducting sphere of mass M is attached to a string of length L. It is at rest in a uniform electrical field of magnitude E directed due right. The sphere has a charge of Q and the string makes a 30 degree angle with the electric field.

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a. Calculate the tension in the string if M = .002 kg, L = .45 M, Q = 10*10^-6 columbs

b. Calculate the magnitude of the Electric field.

c. Desrcibe what the mation of the conducting sphere would be if the string is cut

Homework Equations


E = k(q/r^2)


The Attempt at a Solution


a. Fg = Ft cos Theta
(.002 *10) = ftcos30
ft = .023 N

b. E kq/r^2
E = 9 * 10 ^9(10*10^-6)/.45^2 = 444444.4 N/C

c. The coundcting sphere will move down and to the right

I'm not if I got any of the parts can someone please help me out
 
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a) should be correct
b) what you want is the magnitude of the uniform electric field, not the field produced by the point charge, might want to use Newton third law to relate columb force to tension in part a
c) if you remove the string what are the forces acting on the sphere?
 
ok i got a and c. but I'm having trouble with b. I'm not getting how i should relate the 3rd law to relate the columb force to the tension
 
well coulomb force can be expressed as F=qE , draw a force diagram like in part a and sum of forces equal zero...
 
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