Electrostatics (conduction) and polarization.

AI Thread Summary
When a positively-charged rod touches a metal sphere on an insulating stand, positive charge from the rod transfers to the sphere due to conduction, as like charges repel. Upon removal of the rod, the positive charge redistributes evenly across the sphere's surface, remaining there because the insulating stand prevents charge dissipation. The discussion emphasizes the role of delocalized electrons in metals, which are free to move and carry charge. Additionally, the interaction between the positively-charged balloon and the wooden wall involves polarization, where the balloon induces a charge separation in the wall's molecules, creating an oppositely-charged surface. Understanding these concepts is crucial for accurately addressing electrostatics problems.
ThetaPi
Messages
9
Reaction score
0

Homework Statement



Describe how a metal sphere on an insulating stand is charged if a positively-charged rod were to touch the sphere. (This is a 5 mark problem, so at least 5 major points should be included in the answer. I am not sure whether I have fully answered the problem.)

Homework Equations



Not applicable, of course.

The Attempt at a Solution



The electric charge is created by conduction (charging by contact). When the positively-charged rod touches the sphere, some of the positive charge from the rod spreads onto the metal sphere because like charges repel one another. When the rod is removed, the positive charge spreads evenly over the metal sphere and remains there since the insulating stand prevents the flow of the charge to the ground. The positively-charged rod has given the sphere a positive charge.

I have another problem which I have no idea as to how to solve it:

Homework Statement



A positively-charged balloon will stick to a wooden wall by polarizing molecules in the wooden wall to create an oppositely-charged surface. Describe how the charges are aligned on both the balloon and the wall. (This is a three-mark problem.)
 
Last edited:
Physics news on Phys.org
ThetaPi said:

The Attempt at a Solution



The electric charge is created by conduction (charging by contact). When the positively-charged rod touches the sphere, some of the positive charge from the rod spreads onto the metal sphere because like charges repel one another. When the rod is removed, the positive charge spreads evenly over the metal sphere and remains there since the insulating stand prevents the flow of the charge to the ground. The positively-charged rod has given the sphere a positive charge.
[/I]

As a teacher, I would not yet give you full points for this answer. Remember, this is a solid conductor. Think of the actual particles that are moving about and carrying the charge from one object to the other? What are they called, and which way do they actually move?
 
They are electrons. In metals, they are evenly and randomly distributed throughout the sphere since they are free to move? Delocalized electrons? I don't know. Please guide me on this.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top