Electrostatics - infinite plates

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Homework Help Overview

The problem involves two infinite conducting plates with charges 2q and -q, and the objective is to determine the charge distribution on the surfaces of each plate while the system is in equilibrium.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the electric field associated with infinite plates and its implications for the charge distribution. There are attempts to apply Gauss's law to derive relationships between the charges on the plates. Questions arise regarding the conditions within the conducting material and how to formulate additional equations to solve for the unknown charges.

Discussion Status

The discussion has progressed with participants sharing insights and equations derived from their reasoning. Some guidance has been provided regarding the use of Gaussian surfaces to isolate individual charges, leading to a set of equations that relate the charges. However, there is no explicit consensus on the final charge distribution as the conversation includes various interpretations and approaches.

Contextual Notes

Participants are operating under the assumption that the system is in equilibrium and that the electric field inside the conducting plates is zero. There are also constraints related to the total charge on the system and the relationships between the charges on the surfaces of the plates.

Gil-H
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Homework Statement


Consider two infinite conducting plates of some thickness with charge 2q and -q.
The system is in equilibrium, which means there's no charged particles in motion.
Find the charge distribution on the surfaces of each plate.
(designated as q1 q2 q3 and q4)


Homework Equations





The Attempt at a Solution


All I know about infinite plates is that the electric field is σ/2ε0.
But that doesn't seem to help me here
 

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Gil-H said:
All I know about infinite plates is that the electric field is σ/2ε0.
But that doesn't seem to help me here
Use that to figure out the field between the plates.

Hint: What's the field within the conducting material? Apply Gauss's law.
 
Thanks. You gave something to think about.
But I'm not sure I follow completely.

Because the field inside each plate is zero,
I used gaussian surface which encloses q2 and q3,
and that leads me to that:
q2 + q3 = 0,
and together with:
q1 + q2 = 2q
q3 + q4 = -q
I have three equations.

I need to get one more. How?
 
How about using some gaussian surfaces that enclose only one of the charges at a time?
 
Now I got that!
Thank you very much!

By doing that I achieved that:
q1 + q2 + q3 = -q4
q2 + q3 + q4 = -q1

and with:
q1 + q2 = 2q
q3 + q4 = -q

I ended up with:
q1 = 0.5q
q2 = 1.5q
q3 = -1.5q
q4 = 0.5q

which is the correct answer! :-)
 

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