Electrostatics of balls on a string

[Yuravian]

Homework Statement

In Fig. 21-42 (I attached an MSPaint rendition of it), two tiny conducting balls of identical mass m and Identical charge q hang from non-conducting threads of length L. Assume \theta is so small that tan \theta can be replaced by its approximate equal, sin \theta. (a) Show that x=(\frac{q^2L}{2\pi\epsilon_{0}mg})^{1/3} gives the equilibrium separation of the balls. (b) If L=120cm, m=10 g, and x=5.0 cm, what is |q|?

Homework Equations

Well, I think Coulomb's law is clearly involved because of the \frac{1}{2\pi\epsilon_{0}} bit, which is equal to 2*k.
So then, restating Coulomb's law: F=\frac{1}{4\pi\epsilon_{0}}*\frac{\left|q_1\right|\left|q_2\right|}{r^2}

The Attempt at a Solution

The problem here is I don't know how to start the problem. It appears simple enough but I can't seem to get an answer out of it. Here is what I was thinking: since q_1 and q_2 are both the same, the top bit of coulomb's law becomes q^2 since any number squared is positive (no need for abs. value). splitting out coulomb's law from the full equation within parenthesis gives x=(\frac{1}{4\pi\epsilon_{0}}*\frac{q^2}{r^2}*\frac{2Lr^2}{mg})^{1/3}. The problem with this is that I had to work in \frac{r^2}{r^2}, when I'm pretty sure there's an equivalency in there somewhere.

 

[Doc Al]

Pick one of the balls (the left one, say) and analyze the forces acting on it. The Coulomb force is just one of the forces involved. Hint: Consider vertical and horizontal components separately.