Elementary - braking force of a trolley

AI Thread Summary
A trolley weighing 16,000 kg is moving at 6 m/s and needs to stop over a distance of 10 m. The problem involves calculating the braking force and the time required to stop, but the user is struggling with two unknowns: force and time. The equations of motion and energy relationships are discussed, with a focus on solving a quadratic equation derived from the motion equations. The user expresses confusion about their calculations, particularly regarding the acceleration and the resulting values. Clarification on the correct approach to solving the equations and identifying any mistakes is sought.
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Homework Statement



A trolley weighing 16 000kg is moving along a horizontal surface with a velocity od 6m/s. What braking force would cause it to brake on a distance of 10m and how long it would take?

Homework Equations



a = F/m = ΔV/t

The Attempt at a Solution



So ΔV = 6m/s, m=16 000kg, s = 10m and F = mΔV/Δt. We know neither F nor t so how could I solve this? It's just one equation but two unknown variables. Could you please help?
 
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Do you know the relationships between the work done by a force acting on a body and its energy?
 
I know Newton's laws of motion, that's why I have the a=F/m, but what does that give me?
 
If a, acceleration, is constant, then v= at+ v0 and d= (1/2)at^2+ v0t.

You know that v0= 6 m/s and that d= 10m . Solve the quadratic equation (1/2)at^2+ 6t- 10= 0 for t, with parameter a. The final velocity was 0 so at+ 6= 0. Put the result you got for t into that and solve the resulting equation for a.
 
Rather have a look at the chapter on work and energy.
 
Do you know what the answer should be?
 
HallsofIvy - OK, thank you. So we get t = (2 (sqrt(5 a+9)-3))/a (the other one is negative so doesn't matter), we plug it into the latter and get (2 (sqrt(5 a+9)-3) so (sqrt(5 a+9)=3 but then... a would have to be 0, which it's not, is it? Where did I make a mistake?
 
Could someone please tell me where did I make a mistake? :(
 
No matter what I do to the expression, it never outputs anything other than 0 - why? Do I lack some variable?
 
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