Elementary probability question: dice roll

AI Thread Summary
The discussion centers on calculating the probability of rolling a 1 or a 4 on a die over 12 rolls, where these outcomes are considered successes. Participants clarify whether the inquiry is about the probability of success in a single roll or across all rolls. The probability of not rolling a 1 or 4 is emphasized, suggesting that this can be calculated by multiplying the probabilities of failure for each roll. Once the failure probability is determined, calculating the success probability becomes straightforward. The conversation highlights the need for clarity in defining success and failure in the context of multiple rolls.
Mathman2013
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Homework Statement



Lets say you role a single honest dice 12 times. Where succes is either if the die shows 4 og 1 eye.

My question is what is the probability of sucess or failure?

Homework Equations

The Attempt at a Solution


Is it binomial or conditional probability?
 
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It is not clear to me what question you are asking. Please quote the problem exactly as given.
 
You roll one die 12 times if the die shows either 4 or a 1 it is success if it shows non 1 or non 4 for the remaining rolls then its a failture.

What is the probability of success or failure during the 12 rolls?
 
You are still not explaining what probability you are after very well. Are you after the probability of success/failure in one particular roll? If not, what do you consider success/failure during the 12 rolls?
 
So is it a success if we get a 1 or 4 on the first roll (not needing to roll anymore)? Is it also the same success if we fail 11 times and roll a 4 or 1 on the last roll?

If that is what you want, then you can do something like this: (prob of NOT rolling 1 or 4) AND (prob of NOT rolling 1 or 4) AND . . . AND (prob of NOT rolling 1 or 4).
Turn each of those AND's into multiplication, and assign a number for (prob of NOT rolling 1 or 4), and you have the probability that it will fail (Not rolling a 1 nor a 4 in 12 rolls).

Once you have that, calculating probability of success is straightforward.
 
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