Emergency A Half Angle Question.

  • Thread starter Thread starter getcarter
  • Start date Start date
  • Tags Tags
    Angle
AI Thread Summary
The discussion focuses on verifying the trigonometric equation tanh(z/2) = [sinh x + i sin y] / [cosh x + cos y], where z is a complex number. The user attempted to solve the equation from the right-hand side but encountered difficulties, leading to a simplification of tanh(z/2) as (e^z - 1) / (e^z + 1). Various relevant equations related to complex trigonometric functions are referenced to aid in the verification process. The user expresses a need for assistance in confirming the validity of the equation. The conversation emphasizes the challenge of working with complex numbers in trigonometric identities.
getcarter
Messages
35
Reaction score
0

Homework Statement


How to verify this trigonometric equation? tanh z/2?
verify that:

tanh (z/2) = [sinh x + i sin y] / [cosh x + cos y]


z is a complex number.

How can i verify this equation?


Homework Equations


9957458708fa15c0a09a44ef7e3fbef8.png


http://mathworld.wolfram.com/images/equations/HyperbolicTangent/Inline3.gif
# sin(x + i y) = sin(x) cosh(y) + i cos(x) sinh(y).
# cos(x + i y) = cos(x) cosh(y) - i sin(x) sinh(y).
# tan(x + i y) = (tan(x) + i tanh(y)) / (1 - i tan(x) tanh(y)).
# cot(x + i y) = (cot(x) coth(y) - i) / (i cot(x) + coth(y)).




The Attempt at a Solution



i have tried to solve from right hand side but it didn't work, then i have simplified the equation tanh(z/2) = e^z-1 / e^z+1


if you help me, i will be appreciate.
thanx a lot.
 
Physics news on Phys.org
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top