EMF between quarks & electrons

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SUMMARY

The discussion centers on the electromagnetic force (EMF) interactions between quarks and electrons. It establishes that while quarks possess fractional charges (1/3e), they can still interact electromagnetically with electrons, which have a charge of e. However, in scenarios involving quarks, the strong force, mediated by gluons, predominates over the electromagnetic force. The presence of EMF is not solely dependent on the magnitude of charge but rather on the nature of the interactions involved.

PREREQUISITES
  • Understanding of electromagnetic force (EMF)
  • Knowledge of quark fractional charges (1/3e)
  • Familiarity with the strong force and gluon mediation
  • Basic principles of particle physics
NEXT STEPS
  • Research the role of gluons in mediating the strong force
  • Explore the implications of fractional charge in particle physics
  • Study the electromagnetic interactions in quantum field theory
  • Investigate the observable effects of EMF in particle collisions
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Physicists, particle physics students, and anyone interested in the fundamental interactions between subatomic particles.

werunom
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Hello.

> Is there any electromagnetic force of repulsion between two quarks?
> And, hypothetically speaking [as independent quarks are not observable], could there be EMF of attraction between an electron and an independent quark?

Actually, both the questions boil down to the following - am I correct in saying that EMF is "observable", "present" when the charges involved is e or more than that? That is, when one of the charges involved is a fractional e [as in the case of quark, 1/3e], there is no observable EMF or some other force dominates.

Let me know if I am correct or wrong.

Thanks
 
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Since the quarks and the electrons are electrically charged, they can interact electromagnetically (at least in theory). The same can be said about quarks alone, or electrons alone. When quarks are involved, other <forces> (like the strong one mediated by the gluon field) dominate the e-m one, but that doesn't mean that the e-m one is not observable, or being not observable depends on whether the charge is under 1e or not.
 
Thanks bigubau for confirming & answering. Helped!
 

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