- #1
lando45
- 84
- 0
Hey,
I got this question in a homework from a teacher of mine:
"A car battery with a 15.0 V emf and an internal resistance of 0.0430 is being charged with a current of 62.5 A. What is the potential difference across its terminals?"
I've tried nearly every formula I know on it. EMF = IR + Ir gives me:
15.0 = (62.5 x R) + (62.5 x 0.0430)
15.0 = (62.5 x R) + 2.6875
62.5 x R = 12.3125
R = 0.197
If I then use that value in V = IR I get:
V = 62.5 x 0.197 = 12.3125
I tried that answer but it's incorrect...please, this is driving me nuts! Can anyone help me out? Does this seem like an incredibly hard question for a 16 year old?!
I got this question in a homework from a teacher of mine:
"A car battery with a 15.0 V emf and an internal resistance of 0.0430 is being charged with a current of 62.5 A. What is the potential difference across its terminals?"
I've tried nearly every formula I know on it. EMF = IR + Ir gives me:
15.0 = (62.5 x R) + (62.5 x 0.0430)
15.0 = (62.5 x R) + 2.6875
62.5 x R = 12.3125
R = 0.197
If I then use that value in V = IR I get:
V = 62.5 x 0.197 = 12.3125
I tried that answer but it's incorrect...please, this is driving me nuts! Can anyone help me out? Does this seem like an incredibly hard question for a 16 year old?!