Chemistry Empirical and Molecular Forumla calculation

AI Thread Summary
Reductic acid has a composition of 52.63% carbon, 5.30% hydrogen, and 42.07% oxygen by mass, leading to an empirical formula of C5H6O3. To determine the molecular formula, the number of carbon atoms in 1.23 g of reductic acid is calculated and compared to the given 3.25x10^22 atoms of carbon. The ratio derived from these values helps to identify the molecular formula. Finally, the mass of one molecule of reductic acid can be calculated using Avogadro's number. The discussion focuses on the calculations necessary to derive the molecular formula and the mass of a single molecule.
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Homework Statement



Reductic acid contains 52.63% carbon, 5.30% hydrogen and 42.07% oxygen by mass.
a) Determine the empirical formula of reductic acid

b) If 1.23 g of reductic acid contains 3.25x10^22 atoms of carbon, what is the molecular formula of reductic acid ?

c) Calculate the mass of one molecule of reductic acid.


Homework Equations



-

The Attempt at a Solution



I already found that the empirical formula and found that to be C5H6O3. But I can't seem to get the other parts. Thanks for the help.
 
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Use the molecular mass of the empirical formula to find the number of carbon atoms that there would be in 1.23 g and then compare this to the actual number of carbons given in the problem

e.g.

1.23 g ( moles / g = MW of C5H6O3 ) = moles of C5H6O3

convert this to atoms of C5H6O3 and then this to atoms of Carbon = x

3.25 X 10 ^ 22 atoms of carbon / x = the number factor to multiply your empirical formula to find the molecular formula.




For the next part simply use Avogadro's number.
 
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