End of Classical String - Boundary Condition Explained

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The boundary condition for a classical vibrating string requires that the spatial derivative at the free end be zero, indicating no slope at that point. This can be intuitively understood through the concept of wave reflection, where any disturbance reaching the end of the string reflects back without inversion, resulting in a doubling of the wave amplitude while canceling the derivative. Additionally, real strings may exhibit end corrections that can affect these idealized results. The discussion emphasizes the importance of understanding wave behavior and boundary conditions in classical physics. Overall, grasping these concepts is crucial for accurate predictions in string dynamics.
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The free end of a classical vibrating string imposes the boundry condition that the spatial deriviative of the string at the end must be zero. I can hand wavingly argue this with free body diagrams and manipulate the differential force approximations but i can't come up with a terse intuitive explanation of this boundry equation. any help?
 
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Another way of getting the result is that there is a 100% reflection of any disturbance propagating toward the end, and this reflection is uninverted. When you sum the incident and reflected waves, y(x) doubles, but y'(x) cancels.

This question belongs in the Classical Physics forum.
 
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