Energy and Simple Harmonic Motion of block

AI Thread Summary
The discussion revolves around calculating the elastic potential energy of a spring-mass system when a 3.2-kg block is replaced by a 5.0-kg block. The key point is that while the block is stationary, it indicates that the spring is stretched but not at its equilibrium position, meaning the extension 'x' is constant. Participants clarify that the gravitational force acting on the block and the spring constant remain unchanged, allowing for a ratio-based approach to find the new elastic potential energy. The relationship between the masses and their respective extensions is crucial for solving the problem. Understanding these concepts is essential for accurately determining the elastic potential energy in this scenario.
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Homework Statement



A 3.2-kg block is hanging stationary from the end of a vertical spring that is attached to the ceiling. The elastic potential energy of this spring/mass system is 1.8J. What is the elastic potential energy of the system when the 3.2-kg block is replaced by a 5.0-kg block?

Homework Equations



Elastic potential energy=1/2kx^2
Gravitational potential energy=mgh

The Attempt at a Solution


Help me please!
 
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The problem is that you have the extension x of the spring in your formula, which you do not know. However, there is an extra clue in the word "stationary". What does that mean?
 
it is not moving, x=0?
 
What should I put in for h and k? Thank you, CompuChip!
 
Exactly, it is not moving. But that does not mean that x = 0 (then the spring would be in its equilibrium position... but it is stretched by the mass that's hanging on it)... it merely says that x is a constant. But what can you say about the net force acting on the block. Which forces are there?
 
'x' is the extension from the equilibrium point in the spring when the 3.2kg mass is changed to 5kg. Because 'g' and 'k' stay constant it is just simple ratios...
 
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