Energy gap calculation for semi-conductors.

AI Thread Summary
The discussion focuses on the energy gap required for solar cell materials to effectively absorb solar radiation, particularly wavelengths of 1 µm or less. It is calculated that the energy gap should be approximately 1.24 eV to absorb this radiation, and silicon, with an energy gap of about 1.14 - 1.17 eV, is deemed suitable for solar cells. Concerns are raised about silicon's ability to absorb shorter wavelengths, as energy gaps increase with decreasing wavelength. However, it is noted that modern solar cells often incorporate multiple layers of materials to enhance absorption across a broader spectrum. This layered approach allows silicon to remain a viable option despite its limitations with certain wavelengths.
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Homework Statement


Most solar radiation has a wavelength of 1 µm or less.

(a) What energy gap should the material in a solar cell have if it is to absorb this radiation?
(b) Is silicon an appropriate solar cell material?

Explain your answer.

Homework Equations



f = c/lambda
E = hf

The Attempt at a Solution



a) f = 3E8/1000E-9 = 3E14 Hz

E = hf

So E ≤ 1.24eV

b) Yes, because silicon has an energy-gap of roughly 1.14 - 1.17eV so 1.24eV is enough to excite the electrons into the conduction band.


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What I don't fully understand is if the wavelength is below this 1000nm mark, the associated energy gap is going to increase, very quickly certain wavelengths aren't going to be absorbed by silicon for it to act as a semi-conductor. So I'm thinking my answer is wrong?

For e.g. if the wavelength was 700nm, then E = 1.77eV, and silicon and a lot of other semi-conductors wouldn't be able to utilize these kinds of wavelengths.
 
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Nvm, I found out that most solar cells have layers of other material to absorb different wavelengths to be more efficient, so it was correct.
 
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