GRB 080319B said:
... does this mean that there is no bound to the amount of thermal energy that can exist in a system? I thought there was a bound at the amount of energy/mass that can be in one place before a black hole is created?
You are assuming that the particles in the system stay within the same volume ("in one place") as it is heated. A star with just over ten solar masses has enough gravitational energy to form a black hole. While the star still has nuclear fuel to burn, the thermal energy of its gas particles is enough to resist it collapsing to a black hole. If we somehow added even more energy to the star it would expand, increasing its volume and reducing its density preventing it becoming a black hole. When the star runs out of nuclear fuel, it collapses rapidly, releasing a great deal of gravitational potential energy which creates a supernova explosion ejecting matter all over the place but enough mass remains to form a black hole.
GRB 080319B said:
..... Does one have to add more energy to an incoherent system than a coherent system to arrive at the same average speed of each particle? I would think that the collisions taking place in an incoherent system would cause it to radiate more energy as heat, and subsequently take longer for individual particles to speed up, than a coherent system.Therefore, would it take less time to accelerate the particles in a coherent system to a certain speed than heat up particles in an incoherent one?
In the brick example you would have to insulate the brick that you are heating up to make it a fair comparison.
GRB 080319B said:
Do incoherent systems radiate more energy as heat than coherent systems?
Yes
GRB 080319B said:
I've also heard the reason why a object would require an infinite amount of energy to accelerate to the speed of light was because the mass of increases as the speed of the object increases.
This is a difficult subject. Classically mass increases with relative velocity. The formal modern view is that rest mass is invariant and we do not discuss relativistic mass. One reason for this is that an object moveing at a very high relative speed to the observer might be considered to have enough mass within a given volume to become a black hole. To an observer comoving with the object, it is not a black hole. An object that is a black hole to one one observer while not a black hole to another observer is clearly a contadiction. Einstein said there is no clear definition of mass. Like I said, it is not an easy subject.
Consider a particle fired horizontally from a tower at 0.8c relative to an observer on the tower. Say that observer measures 10 seconds for that particle to fall to the ground. (It is a very long flat planet :P) To an observer comoving with the particle it takes 6 seconds for the particle to fall to the ground. Assuming the the height of the tower and mass of the planet are such that the difference in gravitational time dilation between the top of the tower and the ground is negligable then why the difference?
GRB 080319B said:
Is it true that particles in an incoherent system become more massive as their thermal energy is increased?
Once again this is difficult to answer, if we can not talk about relativistic mass. What we can note, is that if we have a very hot brick and a very cold brick that it will take more energy to accelerate the the hot brick to a given velocity than the cold brick. The hot brick is harder to accelerate. Some people interpret that as the hot brick having more inertial mass (more resistance to acceleration) than the cold brick.
GRB 080319B said:
I though as an object approached the speed of light, its mass increased, not its temperature.
As I said before, the formal approach is that its mass does not increase, but it does resist acceleration more. I think the more formal version is that the momentum energy of the system increases. As for the temperature, the experts are not agreed on whether it increases or decreases or something in between.
GRB 080319B said:
I would think though that adding energy to a system in the form of speeding it up would make it hotter?
Well, at least some of the energy has to spent on speeding up the system and increasing the overall (coherent) momentum of the system). This usually involves ejecting mass in the opposite direction so that momentum of the universe is conserved. The difficulty comes when analysing the motions of individual particles in a moving system in deciding how much of the motion is coherent and how much is incoherent. I have been looking at it for a while and it is not easy, and papers on the subject disagree.
GRB 080319B said:
Why would it lose energy as heat? Would this cooling reduce the objects speed in any way, or make the object less massive?
See all the above.
GRB 080319B said:
I assume by the last sentence of this quote that the relation between relativity and thermodynamics is still not completely understood, so if these questions are unanswerable at this time I understand. Thank you.
Here are some papers on relativistic thermodynamics if you want to sift through them:
P' and T' are the transformed pressure and temperature.
P' = Py^2 , T' = Ty
http://arxiv.org/PS_cache/arxiv/pdf/0712/0712.3793v2.pdf
P' = ? , T' = ?
http://arxiv.org/PS_cache/physics/pdf/0303/0303091v3.pdf
P' = ? , T' = ?
http://arxiv.org/PS_cache/gr-qc/pdf/9803/9803007v2.pdf
P' = P , T' = Ty
http://arxiv.org/PS_cache/arxiv/pdf/0801/0801.2639v1.pdf
P' = P , T= T/y
http://arxiv.org/PS_cache/physics/pdf/0505/0505004v2.pdf
P' = P, T= T/y is my interpretation of the last paper but they do not spell it out. Tolman's book on relativity and thermodynamics also concludes P' = P, T= T/y but the book is rather old.