Energy Loss in a Collision: Calculating Speed and Percentage

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SUMMARY

The discussion focuses on calculating the final speed of a block after a collision with a clay ball and determining the percentage of energy lost in the process. The clay ball, weighing 40.8 g, collides with a stationary 3.41 kg block on a frictionless surface, resulting in a final speed of 0.0596 m/s. The correct formula for calculating the percentage of energy lost is 100 - ((E_initial - E_final) / E_initial) x 100, emphasizing that the initial energy must be used in the denominator.

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  • Familiarity with basic algebra for solving equations
  • Concept of energy loss in inelastic collisions
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Homework Statement



A 40.8 g ball of clay hits and sticks to a 3.41 kg block sitting at rest on a frictionless surface. What is the speed of the block after the collision if the initial speed of the ball of clay is 5.04 m/s?
b)What percentage of the system's initial energy is lost?

Homework Equations



pinitial=pfinal, E=0.5mv2

The Attempt at a Solution



for the first part i figured out the speed final which is 0.0596 m/s
for the second part for each i figured the initial energy and then the final energy using the energy equation for both objects involved. after this part i am stuck to figure out the energy lost i came up with this equation 100-(Einitial-Efinal/Efinal) x100.. i used it and am not getting the right answer..pls. help
 
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Divide by initial energy, not final energy (that's what it means by "percentage of the initial energy").
 
thanks :)
 

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