Energy of scattering photon and emitted electron

AI Thread Summary
The discussion focuses on calculating the energy of a scattered photon and emitted electron using the Compton effect. Given a photon energy of 0.3 MeV and a scattering angle of 120 degrees, the formula derived is E' = (mc^2E) / (2E sin²(φ/2) + mc²). The mass of the photon is zero, while the mass of the emitted electron is approximately 9.11 x 10^-31 kg. Understanding these masses is crucial for applying the Compton effect correctly in this scenario. The calculations emphasize the relationship between photon energy, scattering angle, and the resulting energy of emitted particles.
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Homework Statement


Photon of energy E=0,3MeV is scattering at an angle \phi=\frac{2\pi}{3}. Calculate the energy E' of scattered photon and emitted electron.

Homework Equations


-Compton effect

The Attempt at a Solution



By Compton effect, \frac{hc}{E'}-\frac{hc}{E}=\frac{2hc}{mc^2}\sin^2\frac{\phi}{2}\Rightarrow E'=\frac{mc^2E}{2E\sin^2\frac{\phi}{2}+mc^2}

What is the value of a mass m of scattered photon and emitted electron?
 
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You can look up the masses, but you should certainly know the mass of a photon, and a rough estimate for the mass of an electron. One of them wouldn't make sense in this context.
 
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