SHM: Half Energy at Displacement

In summary, when the displacement in SHM is one-half the amplitude, the fraction of total energy that is kinetic energy is 1/2 and the fraction that is potential energy is also 1/2. The energy of the system is half kinetic energy and half potential energy at a displacement of xm/sqrt(2) or -xm/sqrt(2).
  • #1
mbrmbrg
496
2

Homework Statement



(a) When the displacement in SHM is one-half the amplitude xm, what fraction of the total energy is kinetic energy?

(b) What fraction is potential energy?

(c) At what displacement, in terms of the amplitude, is the energy of the system half kinetic energy and half potential energy?

Homework Equations



[tex]U=\frac{1}{2}kx^2[/tex]

[tex]K+U=E[/tex]

[tex]E=\frac{1}{2}kx_m^2[/tex]

The Attempt at a Solution



I got parts (a) and (b) quite neatly, and I'm convinced that I got (c) also, only WebAssign isn't so convinced.

WORK FOR PART C:
[tex]U=\frac{1}{2}E[/tex]

[tex]\frac{1}{2}kx^2=\frac{1}{2}(\frac{1}{2}kx_m^2)[/tex]

some halfs and k's cancel, leaving

[tex]x^2=\frac{1}{2}x_m^2[/tex]

[tex]x=\frac{x_m}{\sqrt{2}}[/tex]

:eek:
 
Last edited:
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  • #2
That's correct, and so is -xm/sqrt(2), since the question asked for displacement.

How did you enter the answer? Maybe it was expecting the answer in some other format.
 
  • #3
neutrino said:
How did you enter the answer? Maybe it was expecting the answer in some other format.

Thanks; that was it. I entered xm/sqrt2, but they wanted xm/sqrt(2). Looks the same when you click the eyeball to ask what it'll look like!
 

What is SHM and how does it relate to half energy at displacement?

SHM stands for Simple Harmonic Motion, and it refers to the motion of an object that oscillates back and forth around an equilibrium point. Half energy at displacement refers to the principle that when an object in SHM reaches its maximum displacement from equilibrium, it possesses half of its maximum potential energy.

What is the equation for calculating the energy of an object in SHM at a given displacement?

The equation for calculating the energy of an object in SHM at a given displacement is E = 1/2kx^2, where k is the spring constant and x is the displacement from equilibrium.

How does the concept of half energy at displacement apply to real-world systems?

The concept of half energy at displacement applies to real-world systems as it helps us understand the relationship between an object's potential energy and its position in SHM. It can be used to analyze and predict the behavior of various systems, such as pendulums, springs, and even sound waves.

What is the significance of half energy at displacement in the study of SHM?

The concept of half energy at displacement is significant in the study of SHM as it allows us to determine the maximum potential energy of an object at a given displacement. It also helps us understand the conservation of energy in SHM and how energy is constantly exchanged between potential and kinetic forms.

How does the amplitude of an object's motion affect its energy in SHM?

The amplitude of an object's motion in SHM is directly proportional to its energy. This means that as the amplitude increases, so does the energy, and vice versa. Therefore, an object with a larger amplitude will have a greater potential energy at a given displacement compared to an object with a smaller amplitude.

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