Energy released in nuclear fission problem

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Homework Statement



21b10ci.png


Homework Equations





The Attempt at a Solution



(a) Shown.

(b) W = 975 MeV

(c) Initially nucleus has volume V. Splits into two smaller particles each with charge Q/2, and volume V/2. So for each particle, Q/2 and R*(1/2)1/3

So, W' ~ 2 * [(0.5)2/(0.5)1/3] = (0.5)2/3

ΔW = 360 MeV


I'm not sure if the volume of each is halved or not by their phrasing..
 
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