Energy required to fully ionize Uranium

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The discussion centers on determining the maximum wavelength of light required to fully ionize uranium to U92+, stripping it of all electrons. Participants clarify that the focus should be on the energy needed to remove the outermost electron, as this will dictate the maximum wavelength. It is emphasized that only the hardest-to-remove electron, typically the one closest to the nucleus in the ground state, needs to be considered for this calculation. The confusion arises from the distinction between total ionization energy and the energy of the highest energy photon required. Ultimately, understanding this concept is key to solving the problem effectively.
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1. What is the maximum wavelength of light required to fully ionised Uranium to U92+, i.e.
strip it of all electrons and leaving a bare nucleus? For simplicity, only consider direct
ionisation and neglect non-linear effects.





Attempt at solution

Ok, so the electron structure of the atom is 2,8,18,32,21,9,2. Ionization will be the energy required to remove an electron that is the least tightly bound to the atom. In order to completely ionize the atom do I calculate the energy required to ionize each electron at their respective energy levels? I am a bit confused as to how to tackle the problem.
Thanks
 
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doppeled said:
What is the maximum wavelength of light required to fully ionised Uranium to U92+, i.e.
strip it of all electrons and leaving a bare nucleus? For simplicity, only consider direct
ionisation and neglect non-linear effects.

[...]

In order to completely ionize the atom do I calculate the energy required to ionize each electron at their respective energy levels?
I think this is where your confusion is coming from: these two statements of the problem are different.

You are not asked the total energy to ionize the atom, but the highest energy photon needed. Consider that one photon removes one electron, what electron will be the hardest to remove?
 
Ah yes, I think I understand now. So just a matter of calculating the energy required to remove an electron closest to the nucleus, which is in the ground state.

Thank you for your help.
 
doppeled said:
Ah yes, I think I understand now. So just a matter of calculating the energy required to remove an electron closest to the nucleus, which is in the ground state.
Just to make clear, it will be the energy needed to remove the last electron.
 
Yes so during ionization the outermost, least bound electrons will be removed first, and so by calculating wavelength required to remove the last electron we have a sufficient energy to completely ionize.
 
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