Energy Required to Lift a Heavy Box

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To lift a heavy box using a pulley, the upward force required is equal to the weight of the box, F = mg, where m is the mass of the box. A misunderstanding arose regarding the mechanical advantage of the pulley; while it can reduce the force needed, it does not decrease the energy required to lift the box. If the pulley is attached to the box, the force remains mg, as the distance over which the force is applied does not change. Clarification on the pulley setup is essential for accurate calculations. Ultimately, the force needed to lift the box with constant velocity is F = mg.
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As you are trying to move a heavy box of mass m, you realize that it is too heavy for you to lift by yourself. There is no one around to help, so you attach an ideal pulley to the box and a massless rope to the ceiling, which you wrap around the pulley. You pull up on the rope to lift the box.


A.) What is the magnitude F of the upward force you must apply to the rope to start raising the box with constant velocity?
Express the magnitude of the force in terms of m, the mass of the box.


I think the answer should be mg/2

is this correct?
 
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Yes. The pulley gives you a mechanical advantage, reducing the force (but not the energy!) needed to lift the box.
 
The pulley won't make it any easier. The force you'll need to apply with a single pulley is still F=mg.

...

Edit: Hmm... I think I might have mistaken the way the pulley is connected, in which case the force may be mg/2. A diagram would be nice!
 
With a single pulley the way you described it there's no way to shorten the distance over which the force is applied (it is the same as the distance over which the pulley rises). So the force is still mg. The only facilitation is that you apply the force downward.
 
Please reread the original post: The pulley is attached to the box, not the ceiling.
 
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