Energy transfer from x altitude to geosynchrous altitlude

AI Thread Summary
The discussion focuses on calculating the energy required to transfer a 280kg satellite from a circular orbit at 400 km altitude to a geosynchronous orbit using a Hohmann transfer. Participants emphasize the importance of applying conservation of energy principles, specifically the equations for kinetic and potential energy in both orbits. The initial kinetic and potential energy must be calculated for the lower orbit, and then the necessary energy for the boost to the higher orbit is determined. The semi-major axis of the elliptical transfer orbit is identified as the average of the two radii involved in the transfer. The conversation concludes with encouragement to apply the appropriate formulas to solve for the energy change.
tnutty
Messages
324
Reaction score
1

Homework Statement



INTRO TO THE PROBLEM :For a circular orbit around a massive gravitating body, the speed depends on the radius according to the equation V = sqrt (GM/r) ; for elliptical orbits, the speed varies according to the equation v^2 = 2GM([ 1/r - 1/(2a), where r is the distance from the massive body and a is the semimajor axis of the ellipse (i.e., half the sum of the closest and farthest distances). A satellite can be transferred from one circular orbit (at radius r1) to a higher orbit (at radius r1) by boosting the circular speed v1 at v2 to the appropriate speed for an elliptical orbit whose distance varies between r1 and r2 , and then boosting the speed in the elliptical orbit at r2 to the circular speed v2. This is called a Hohmann transfer.

THE PROBLEM STATEMENT :
How much energy is required for the first boost in such a transfer to take a 280kg satellite from a circular orbit at a 400 km altitude to the altitude of a geosynchronous orbit?

change in K_1 = _________J

Homework Equations




stated above in the intro

The Attempt at a Solution



clueless?
 
Physics news on Phys.org
The conservation of energy still works doesn't it?

(Potential + Kinetic) before + Energy = (Potential + Kinetic) after?
 
so,

1/2mv^2 - GMm/r = 1/2mv^2 - GMm/r

?
 
tnutty said:
so,

1/2mv^2 - GMm/r = 1/2mv^2 - GMm/r

?

The Δ anyway. Mustn't that be the additional energy?
 
I'm sorry i am confused
 
tnutty said:
I'm sorry i am confused

You have initial potential energy and kinetic energy in lower orbit.

You add energy.

You get a higher orbit with kinetic energy and potential energy.
 
how about saying it mathematically. can you start me off?
 
tnutty said:
how about saying it mathematically. can you start me off?

You have the equation below. I'm sure you can do it.

Besides if it comes up on a quiz, I won't be there to start you off. It's good practice.
 
So what's the formula to delta k ?
 
  • #10
tnutty said:
So what's the formula to delta k ?

Don't they give you the formulas for how to calculate the v2's
 
  • #11
ok. r is the radius of the Earth + 400km and a is ? And that formula above v^2 =...
is delta K ?
 
  • #12
tnutty said:
ok. r is the radius of the Earth + 400km and a is ? And that formula above v^2 =...
is delta K ?

Well that's a good part of it, but strictly speaking you want to be working with ½mv² for KE. so use the v² 's that you find to determine your ½mv² 's.
 
  • #13
How would I represent (a) as? in the equation above?
 
  • #14
Don't look now, but they tell you how to determine a in the problem. If your ellipse is to vary between r1 and r2, what is the semi-major axis?
 
  • #15
(r1+r2) / 2
 
  • #16
tnutty said:
(r1+r2) / 2

That would seem so.

So plug 'em in and get'er done.
 
Back
Top