Entropy change in a reversible adiabatic process

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For a reversible process, the equation dS = dq/T applies, where dq represents the heat exchanged within the system. In an adiabatic process, there is no heat exchange, meaning dq = 0. Consequently, for an adiabatic reversible process, the entropy change dS equals zero, as there is no heat transfer to contribute to entropy change. This reasoning is confirmed as accurate, indicating that the entropy remains constant in such processes. The discussion emphasizes the relationship between heat exchange and entropy in thermodynamic processes.
Bipolarity
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For a reversible process, I imagine it is correct to say that

dS = \frac{dq}{T} where all quantities refer to system quantities (not the surrounding).

However, for an adiabatic process, dq = 0.

Thus, should it be the case that for an adiabatic reversible process,

dS = \frac{dq}{T} = \frac{0}{T} = 0

Please correct me if I am wrong, and point out the flaws in my reasoning.

BiP
 
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Entirely correct.
 

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