Entropy in system of non-degenerate atoms

AI Thread Summary
In a system of non-degenerate multi-level atoms at their lowest energy state, the degeneracy function Ω equals 1, which simplifies the entropy calculation. The entropy S can be determined using the equation S = kbTln(Ω), leading to S = 0 since ln(1) is 0. The discussion also touches on the relationship between temperature and entropy, suggesting that temperature can be inferred from the change in entropy over energy. Calculating temperature directly from entropy may involve more complex equations, but the basic principles remain clear. Understanding these concepts is crucial for solving problems related to thermodynamics in atomic systems.
vodkasoup
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Hi all,

1. Homework Statement

A system of non-degenerate multi-level atoms are all in their lowest energy state. Calculate the entropy of the system.

Homework Equations



S = kbTln(Ω)

S = Q / T

dU = TdS - pdV

The Attempt at a Solution



I'm not sure how to proceed. I know that Ω is the degeneracy function. If all of the atoms in the system are non-degenerate and in their lowest energy level, does this value equal 1 ? If the atoms are in their lowest energy state, what does this say about the temperature?

Many thanks for your help.
 
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vodkasoup said:
I'm not sure how to proceed. I know that Ω is the degeneracy function. If all of the atoms in the system are non-degenerate and in their lowest energy level, does this value equal 1 ? If the atoms are in their lowest energy state, what does this say about the temperature?

Many thanks for your help.
Indeed Ω = 1. This is enough to calculate the entropy. Temperature is often identified by ##1/T = \Delta S/ \Delta E##, so I suppose we could attempt to calculate it this way but it might be more work.
 
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