Entropy of a Schwarzchild black hole

AI Thread Summary
The discussion centers on deriving the entropy of a Schwarzschild black hole, expressed as S = (ξ k c / 4π h G)A, where A is the surface area related to the event horizon. Participants reference the entropy change formula and the de Broglie relation to establish connections between energy and black hole thermodynamics. The conversation highlights the importance of the first law of thermodynamics in the context of black holes, specifically relating mass changes to changes in area and work done. There is also a clarification regarding the correct notation for the Bekenstein-Hawking entropy formula. The thread concludes with a focus on the relationship between thermodynamic equations for black holes.
johnwalton84
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Hi, I'm looking for some help on where to start with this question:

The surface area of a Schwarzschild black hole is A=16 \pi R^2_c where R_c is the distance of the event horizon from the centre of the black hole. Show that for such a hole containing quantized matter, its entropy can be written

S = \frac{\xi k c}{4\pi h G}A

where \xi is a numerical constant.



I know that the enropy of a change is

S = \int_{initial}^{final} \frac{Q_{rev}}{T}

and can show that using the de Broglie relation

\lambda dB <= 2R_c = \frac{4GM}{c^2}

the energy is

\frac{hc^3}{4GM} <= E

But I'm not sure where to go with proving that the entropy is the equation given.
 
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It looks like you got your Latex wrong. Change the [\tex] to [/tex].
 
S_{Beckenstein-Hawking}=\frac{A}{4\hbar}

is more likely defined...

Daniel.
 
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In the section 12.5 of his book [1],Wald shows that the first law of thermodynamics for a black hole can be written

dM=\frac{1}{8\pi}\kappa dA+\Omega_{H}dJ

Daniel.

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[1]Wald R.M."General Relativity",1984.
 
Ok, that's helpful, thanks. I assume \Omega_{H}dJ represents work done.

Does that mean the two forms

dM = \frac{K dA}{8\pi} + work
dE = T dS + work

could be equated?

dE - T dS = dM - \frac{K dA}{8\pi}
 
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Yes,TdS=\frac{1}{8\pi}\kappa dA

Daniel.
 
And one more thing,it's Karl Schwarzschild.

Daniel.
 
Thanks for your help.
 
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