Deriving Standard Molar Entropy of Water

  • Thread starter Thread starter dbrittain
  • Start date Start date
  • Tags Tags
    Entropy Water
AI Thread Summary
The standard molar entropy of water varies in literature, with values around 63.45 J/mol-K to 69.9 J/mol-K commonly cited. To derive the standard molar entropy of liquid water, one can start with the entropy of gaseous water and adjust it by subtracting the heat of vaporization divided by the standard absolute temperature. Additionally, knowledge of the equilibrium constant for the formation reaction is essential for accurate calculations. This approach highlights the importance of thermodynamic principles in determining entropy values. Understanding these derivations is crucial for physics and chemistry students studying thermodynamics.
dbrittain
Messages
1
Reaction score
0
Hello everyone, I am a second year physics student attending university, and I have a question about how the actual Standard Molar Entropy of various molecules are found and derived. I have been looking through various Thermodynamics and Chemistry books as well journals online and have all referenced water, for example, to have a standard entropy of around 70 (some are more specific, stating 63.45 J/mol-K etc, but others including some chemistry books state the standard molar entropy to be 69.9 J/mol-K.).

I am specifically interested in how the standard molar entropy of water in liquid form was found.

Thanks in advanced,
 
Last edited:
Science news on Phys.org
If you know the standard molar entropy of gaseous water (a hypothetical state), the standard molar entropy of liquid water is that value minus the heat of vaporization divided by the standard absolute temperature. To get the standard molar entropy of liquid water, you need to measure (or otherwise know) the equilibrium constant for formation reaction.
 
Thread 'Thermo Hydrodynamic Effect'
Vídeo: The footage was filmed in real time. The rotor takes advantage of the thermal agitation of the water. The agitation is uniform, so the resultant is zero. When the aluminum cylinders containing frozen water are immersed in the water, about 30% of their surface is in contact with the water, and the rest is thermally insulated by styrofoam. This creates an imbalance in the agitation: the cold side of the water "shrinks," so that the hot side pushes the cylinders toward the cold...
Back
Top