zenith8
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OK. Consider a deterministic hidden-variables theory - de Broglie-Bohm pilot-wave theory, say. There are particles as well as the waves, and the particles follow the stream lines of the ordinary QM probability current. No extra equations. It's just QM.Fredrik said:You're asking "how" it can happen in SR, but I don't know what sort of answer you're looking for if the ones I've given you aren't enough. There's no way to use an EPR experiment to synchronize two clocks at spacelike separation. There's no transfer of information, since the wave function isn't measureable. Alice, who does the first measurement, doesn't even use the same wavefunction to represent the state of the two-particle system after her measurement as Bob at the other end at the same time in a frame where Alice's measurement happens first. So it's up to you to explain why you think EPR implies absolute simultaneity. Why would it, when there's no instantaneous transfer of information (or any transfer of information for that matter)? And even if information had been transferred at infinite speed in one inertial frame, why do you assume that the speed is infinite in all inertial frames?
Under ordinary circumstances (particles distributed as psi^2) you can't send instantaneous signals - even though when you measure spin-up then an instantaneous signal passes to the distant arm saying "You're spin down" - it is the case that there is no effect on the expectation values or on the probabilities. The statistical distribution of properties at one end are just the normal ones. and this masks any signalling. So quantum nonlocality cannot in fact be used for practical signalling at a distance. This means that if there were a preferred rest frame, it would be undetectable in practice.
But this isn't a fundamental constraint. From the hidden-variables perspective, it's a peculiarity of a special 'quantum equilibrium' distribution of the particles. The fact we can't detect the rest frame is not an uncomfortable conspiracy seemingly built into the laws of physics - it's just an accident of our living in a state of quantum equilibrium, whose statistical noise masks the underlying nonlocality.
If you do the analysis, hypothetical non-equilibrium distributions (particle distribution not equal to psi^2) do make it possible to use non-locality for instantaneous signalling (just like in stat mech, differences of temperature make it possible to convert heat into work). Proof slightly boring but obvious - trust me for the moment
So to synchronize clocks:
If experimenters at space time events A and B had access to non-equilibrium systems entangled between A and B, then they would be able to signal back and forth to each other instantaneously. In an arbitrarily short time (as measured at each wing) a long conversation could in principle take place, during which (for example) the experimenters agree to set their clocks to read time t=0. They could signal to each other to confirm that they did do this. In such conditions A and B have to be considered as simultaneous events, and the agreed-upon time variable would define an absolute simultaneity. Thus, using non-equilibrium matter, experimenters at remote locations could set their clocks to read the same instantaneous time.
This is true, even though practical difficulties might prevent us from *actually* doing the experiment. It raises the question of how these signals could mesh with the surrounding approximately classical spacetime. This question must have an answer , irrespective of the underlying microscopic theory of spacetime.
Now you might say, well - what if the two wings are in motion relative to each other. So synchronize the clocks at t=0, and then let one of them accelerate and go on a tour then come back to where it was. The clock readings will no longer be the same since the accelerated clock will have slowed down. But this doesn't matter - remember we know have an absolute time - the final clock readings will still be simultaneous events (as could be verified by non-local communication) yet, the readings will not be synchronous.
Note - and this is the fun bit - that if you synchronize your distant clocks by non-local signalling, then the speed of light will be measured to be isotropic *only* in the preferred rest frame. Recall that moving experimenters who assume that the speed of light is still c in all directions would adjust their clocks at different points in space with settings that differ by the term -vx/c^2 (to lowest order in v/c) - see Poincare. In quantum equilibrium, of course, such non-local signalling is impossible and the true rest frame can't be detected.
Which I think explains what you chaps were grumbling about earlier this evening.
Did I get anywhere?
Zenith.