Eq. Logic Expression for Circuit 2

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Discussion Overview

The discussion revolves around determining the equivalent logic expressions for two given circuits as part of a homework assignment. Participants are focused on analyzing the logic gates involved and expressing their reasoning for the outputs of the circuits.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant proposes the logic expression for circuit 2 as (B' + C) * A, explaining the roles of NOT, OR, and AND gates in their reasoning.
  • Another participant confirms the correctness of the expression for circuit 2 and inquires about circuit 1.
  • Multiple participants express difficulty in deriving the expression for circuit 1, with one suggesting a possible expression: (A * (A' * C') * B') + (A * C * B).
  • Some participants suggest starting from the right side of the circuit and working backwards to simplify the process.
  • One participant acknowledges a potential error in their expression for circuit 1 and seeks validation from others, reiterating their expression with slight modifications.
  • Another participant confirms the revised expression for circuit 1 as correct.

Areas of Agreement / Disagreement

There is agreement on the expression for circuit 2, while circuit 1 remains contested with multiple attempts and revisions without a clear consensus on the final expression.

Contextual Notes

Participants express uncertainty regarding the complexity of circuit 1 and the correctness of their proposed expressions, indicating a reliance on visual interpretation of the circuit pathways.

DeathDealer
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Homework Statement


https://www.dropbox.com/s/d3qdr96n27j8wa7/circuit.png?dl=0

The questions is as follows: For each circuit write the equivalent logic expression.

Homework Equations



(B' + C) * A (?) My Attempt at circuit 2
(A* (A' * C') * B') + (A * C * B) My Attempt at Circuit 1


The Attempt at a Solution


[/B]
I attempted circuit 2 and circuit 1 but circuit 2 is easier because i think i know some of the basics but circuit 1 was very complicated (I did look at it and try to work it out, my best guess really) and i really need an assist on that as for circuit 2 here is what I got and my reasoning: (B' + C) * A

In the second circuit you have three gates. A "NOT" gate, a "OR" gate and an "AND" gate.

1) "NOT" gates inverts the input. An input of '1' for a NOT gate would result in a '0' and an input of '0' would result in a '1'. So if the input is say x we denote the output by x′ where x′ denote the opposite of x. So B becomes B'.

2) "OR" gates take two inputs and add then together. Basically this means if the two inputs are x and y the output will be x+y. So B' becomes B'+C

3) "AND" gates take two inputs and multiplies then together. Hence if the two inputs are x and y the output will be xy. So B' + C becomes (B'+C) * A
 
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Yes, that is correct. Have you made an attempt for circuit 1?
 
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axmls said:
Yes, that is correct. Have you made an attempt for circuit 1?
I found it very hard. I know what the gates mean but all those pathways going everywhere is just to confusing. BUT if i had to guess I would say something like: (A* (A' * C') * B') + (A * C * B).
 
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Just start from the right side, and work backwards slowly. Take your time.
 
axmls said:
Just start from the right side, and work backwards slowly. Take your time.

Am I close? (A* (A' * C ') * B ') + (A * C * B)
 
I also came up with some tables is this right?
 

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I think i mucked up circuit 1: its (A* (A' * C ')' * B ') + (A * C * B). Could someone tell me if I'm right?

 

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DeathDealer said:
I think i mucked up circuit 1: its (A* (A' * C ')' * B ') + (A * C * B). Could someone tell me if I'm right?

Yes, that looks correct.
 

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