Equation apply to reversible only or not?

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SUMMARY

The discussion centers on the applicability of the equations Tds = du + pdv and du = dq + dw across different thermodynamic processes. It is established that while these equations are valid for all processes, the relationship dw = -pdv specifically holds true only for reversible processes. The conversation also clarifies that the heat capacity at constant pressure (Cp) is generally dependent on pressure, although it can be treated as independent under specific conditions where dp = 0.

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  • Understanding of thermodynamic equations, specifically Tds = du + pdv and du = dq + dw.
  • Knowledge of reversible and irreversible processes in thermodynamics.
  • Familiarity with the concept of heat capacity, particularly Cp at constant pressure.
  • Basic grasp of Maxwell relations and their implications in thermodynamics.
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  • Learn about the derivation and applications of Maxwell relations in thermodynamic systems.
  • Investigate the factors affecting heat capacity, including pressure dependence and temperature effects.
  • Explore quasistatic processes and their significance in thermodynamic analysis.
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siresmith
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Equation apply to reversible only or not??

My thinking must be faulty somewhere, but I can't work out what's gonig on...

The equation

Tds = du + pdv and

du = dq + dw

are supposed to be valid for all processes right?

yet dw = -pdv only for reversible cases, yes?

So how do you prove that du = Tds + fdx

given that fdx = dw (for a stretched wire) if you don't know if its a reversible process?

As fdx = dw can only be equated with the -pdv if its reversible.

[or similarly, ydA in place of fdw for the surface tension of a droplet. Are you just supposed to know these are reversible?]

Secondly, is Cp, 'heat capacity at constant pressure' independent of pressure?

Anybody know the answers??
 
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Firstly, I agree with what was stated on your first two questions. Those equations do hold for all processes and dw = -pdv is only true given you know it is reversible. The problem, I believe arises since you assume you don't know it is reversible. To answer this think about how your system in this case the wire will respond to certain quasistatic conditions.

According to your equation fdx = dw, if work is done on the wire, it should expand/get stretched. Now slowly reverse the process. Slowly do less work and the wire should begin to shrink. This process seems to me to be reversible.

For the question regarding Cp, it is done at a constant pressure, such that dp = 0. This allows one to calculate it by using Cp = dH/dT (partial derivative). In such a case, it can be shown to be independent of pressure.

Hope this will help.
Cheers CB
 
Col.Buendia said:
For the question regarding Cp, it is done at a constant pressure, such that dp = 0. This allows one to calculate it by using Cp = dH/dT (partial derivative). In such a case, it can be shown to be independent of pressure.

If you're keeping p constant, then of course the pressure dependence of C_p will not appear! In general, C_p is dependent on pressure. It can be shown by using Maxwell relations that for constant T,

\left(\frac{\partial C_p}{\partial p}\right)_T=-VT\left[\alpha^2+\left(\frac{\partial \alpha}{\partial T}\right)_p\right]

where \alpha is the volumetric coefficient of thermal expansion.
 

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