Understanding Internal Energy Changes in Phases of Water

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SUMMARY

This discussion focuses on the internal energy changes of water across its three phases: solid, liquid, and gas, within the temperature range of -10°C to +112°C. The key equation for calculating internal energy is identified as U = m * c * Δθ, where m is mass, c is the specific heat capacity (4.19 kJ kg–1 K–1 for water), and Δθ represents the change in temperature. Participants clarify that Δθ is not the change from absolute zero but rather the temperature change from the initial state. The discussion emphasizes the importance of understanding specific heat capacity and its application across different phases of water.

PREREQUISITES
  • Understanding of thermodynamics principles
  • Familiarity with the concept of specific heat capacity
  • Knowledge of phase changes in water
  • Basic mathematical skills for applying equations
NEXT STEPS
  • Study the first law of thermodynamics and its applications
  • Learn about phase diagrams and the triple point of water
  • Explore the concept of latent heat and its role in phase transitions
  • Investigate the differences in specific heat capacities for various substances
USEFUL FOR

Students studying thermodynamics, educators teaching physical science, and anyone interested in the energy dynamics of water in different states.

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Homework Statement


Sketch a diagram of internal energy (y-axis) versus temperature in the range from -10°C to +112°C to indicate how energy would change for a fixed quantity of water in its three phrases. Label and explain the main features of the variation.

Homework Equations


upload_2017-4-28_21-58-35.png


The Attempt at a Solution


I'm going to show how energy would hange over the 3 phases of freezing whilst a solid, melting from a solid and vapourising from a liquid as well as the triple point.

Thing is I'm not sure whether the first equation mc delta theta is the right one for internal energy alone? Would theta represent the change in absolute temperature from -273 degrees or the particles? I assume it's mass x speed of light x the change in absolute temp or something to do with the particles?

Or is another equation entirely?

Cheers
 
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C in the equation is not the speed of light. Guess again.
 
specific or just normal heat capacity?
 
Day3091 said:
specific or just normal heat capacity?
Specific
 
Okay, cheers. So that is definitely the equation used to find the internal energy of a quantity of water in whatever state? It doesn't change for a gas? There's
upload_2017-4-28_23-27-52.png
and it's relatives in my notes as well and I've got a feeling they may be relevant to gases.

Is theta the change in absolute temperature then?
 
Day3091 said:
Okay, cheers. So that is definitely the equation used to find the internal energy of a quantity of water in whatever state? It doesn't change for a gas? There's View attachment 197422 and it's relatives in my notes as well and I've got a feeling they may be relevant to gases.

Is theta the change in absolute temperature then?
No. ##\Delta \theta## is the change in temperature.

You really need to do some studying in thermo book before you start working on this question. You are lacking the required background.
 
Yeah you're right, I only gave it a general overview. Absolute temp is the difference from -273 degrees isn't it. So mass x specific heat capacity x change in temperature. I just need to find out how the mass changes in phases and states so I can calculate and begin to plot.

The thing is - a mass is only given in part B of the question (Specific capacity of water 4.19 kJ kg–1 K–1) and it isn't specified whether that applies to part A aswell...but it must do for the equation to work. How else am I going to get any values in Joules?
 
Day3091 said:
Yeah you're right, I only gave it a general overview. Absolute temp is the difference from -273 degrees isn't it. So mass x specific heat capacity x change in temperature. I just need to find out how the mass changes in phases and states so I can calculate and begin to plot.

The thing is - a mass is only given in part B of the question (Specific capacity of water 4.19 kJ kg–1 K–1) and it isn't specified whether that applies to part A aswell...but it must do for the equation to work. How else am I going to get any values in Joules?
They only asked for a (rough) sketch.
 
I hope so! It's hard to know whether to take the phrasing literally or not with it being science XD
 

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