Equation of a curve in 3 dimensions

sdevoe
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Homework Statement


A heat-seeking missile is located at (2,-3) on a plane. The temperature function is
given by T(x; y) = 20-4x^2-y^2. Find the equation of the curve along which the
missile travels, if it continuously moves in the direction of maximum temperature
increase. Express your answer in the form x = f(y). Show the calculations.


Homework Equations



T(x; y) = 20-4x^2-y^2

The Attempt at a Solution


I know the missile will travel along the direction of the gradient. The gradient with respect to x is -8x and the gradient with respect to y is -2y. The problem I'm having is getting the equation in terms of x. My only idea is to take δx(2,-3)(x-2)+δy(2,-3)(y+3)=0 and solve for x where x and δy are the gradients with respect to x and y. Is that correct?
 
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sdevoe said:
I know the missile will travel along the direction of the gradient. The gradient with respect to x is -8x and the gradient with respect to y is -2y.

The missile moves in the direction of the temperature gradient at any point of its path. That means that its velocity points in the direction of the gradient vector. But the velocity is tangent to the path. How do you get the tangent of a curve y=f(x)?


ehild
 

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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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