Equation of Tangent: y = -7x + 5 @ (1,1)

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SUMMARY

The discussion focuses on determining the equation of the tangent line to the function y = (3x^-2 - 2x^3) at the point (1,1). Participants confirm that calculating the derivative dy/dx is essential for finding the slope of the tangent line. After obtaining the slope, users can solve for the y-intercept to complete the equation of the tangent line, which is expressed as y = -7x + 5.

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Determine the equation 1 the tangent to the given function, at the given point.

y = (3x^-2 - 2x^3) , @ (1,1)
 
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pretty sure you need to take the derivative of that. The dy/dx (derivative) you get out of that after plugging everything in is your slope of the tangent. Then just solve for your y-intercept.

*edit* The other questions you just posted are really the same idea as this.
 
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